## 1550.16 – Harnessing Horses

Jane bought a harness, a big horse, and a small horse for $4,500 in total. The value of the harness and the big horse together was twice that of the small horse alone. What was the value of the small horse? Note: this problem doesnâ€™t require fancy algebra. Try doing it in your head!

## Solution

The algebra for this is simple. Call the value of the small horse $x$. Then the value of the harness plus the large horse is $2x$. Everything together sums to $4,500. What is everything? It's $2x + x$ or $3x$. In words, three times $x$ is $4,500, so $x$ is a third of this amount, or $1,500. This is the value of the small horse.

We are simply recognizing that the $4,500 is split into three equal parts, with two going towards the harness and big horse, and one going towards the small horse. The problem is to divide $4,500 by three, which is not *that* hard.