1550.18 – Jacob's Bumper

Tags:Problem Set 4Algebra IAlgebra Prep

Jacob agrees to work after school for Mr. Daniels, his school’s head custodian, who says he'll pay Jacob $240 and the front bumper of a 1958 Ford Thunderbird for one year of work, including the summer. Jacob quits after seven months. Mr. Daniels does some calculation and pays Jacob $100 plus the bumper. What did Mr. Daniels decide was the value of the bumper?


Let bb be the value of the bumper. We are given that the value of a whole years work is 240+b240 + b. Therefore,

value of one month’s work =112(240+b)=20+b12.\text{value of one month's work } = \frac{1}{12}(240 + b) = 20+\frac{b}{12}.

So, the value of seven month's work is

7(20+b12)=140+7b12=100+b,7(20 + \frac{b}{12}) = 140 + \frac{7b}{12} = 100 + b,

where the last part of this equality is what Mr. Daniels actually paid Jacob. Solving for bb we get,

b=140+7b121005b12=40,b=$96.\begin{aligned} b &=& 140 + \frac{7b}{12} - 100 \\ \frac{5b}{12} &=& 40, \\ b &=& \$96. \end{aligned}