If x,y and z are such that yz:zx:xy=1:2:3, then x/yz:y/xz is
- 3:2,
- 1:2,
- 1:4,
- 2:1,
- 4:1.
Solution
Let us first find an example of x,y and z such that yz:xz:xy=1:2:3.
A little fooling around suggests x=6,y=3,z=2 and this checks. For these numbers, x/yz=1 and y/xz=1/4. If, as the problem suggests, the answer for any numbers that work is the same, then (e) is correct.
Can we prove it?
It's not so bad:
xzyyzx===xyyx=y2x2y2z2x2z2=(yzxz)222=4.