2150.41 – Adding x to Numerator and Denominator


Let a quantity xx be added to both the numerator and the denominator of a fraction a/ba/b, where neither aa nor bb is 00. Let the new value of the fraction be c/dc/d. Find the value of xx in terms of a,b,c,a, b, c, and dd.


Solution

Cross multiply, then solve for x:

a+xb+x=cd,d(a + x)= c(b + x),ad+dx=bc+cxdxcx=bcad,x(d – c)= bc – ad,x=bcaddc. \begin{aligned} \frac{a + x}{b + x} &=& \frac{c}{d}, \\ d(a + x) &=& c(b + x), \\ a d + d x &=& b c + c x \\ d x - c x &=& b c - a d, \\ x(d – c) &=& bc – ad, \\ x &=& \frac{bc – ad}{d – c}. \end{aligned}

Afterthought: the denominator of that fraction might be zero. Do we need to specify something to keep that from happening? Poke around and see what you find.