Evaluate the sum:
12−22+32−42+52−62+⋯+1992.
Solution
Pair 'em up:
12+(32−22)+(52−42)+(72−62)+…+(1992−1982)=1+5+9+13+⋯+397.
This is an arithmetic progression with 1st term 1, difference 4, and last term 397. The sum of these progressions is
(number of terms) ⋅ (average of the first and last terms)=299(1+397)=19701.