3321.11 – A Circle and A Square


Suppose a circle and a square have the same area. What is the ratio of the area of a square inscribed inside the circle to the area of a circle inscribed inside the square?


Solution

Referring to the diagram below, we are given that πrs=s2\pi r^s = s^2 so that r2=s2/πr^2 = s^2/\pi. We seek the ratio A1/A2A_1/A_2. We have,

A1= half the product of the diagonals =12(2r2r)=2r2,A2=π(s2)2=πs24,A1A2=2r2/πs24=2s2π/πs24=2s2π4πs2=8π2. \begin{aligned} A_1 &=& \text{ half the product of the diagonals } \\ &=& \frac{1}{2} (2r \cdot 2r) = 2r^2, \\ A_2 &=& \pi \left( \frac{s}{2} \right)^2 = \frac{\pi s^2}{4}, \\ \frac{A_1}{A_2} &=& 2r^2 / \frac{\pi s^2}{4} = \frac{2 s^2}{\pi} / \frac{\pi s^2}{4}\\ &=& \frac{2 s^2}{\pi} \cdot \frac{4}{\pi s^2} = \frac{8}{\pi^2}. \end{aligned}

3321_11_solution_5d4f24a01d.png